Quadratic equations are the equations of degree 2 i.e the highest power of the variable is 2. Therefore it has 2 solution or 2 roots.
The standard form of a quadratic equation is
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Where a, b, c are constant numbers, x is the variable and
. Before deriving the general formula for a quadratic equation let us define the two terms.
Discriminant of the quadratic equation (D)
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note that
for real roots of a quadratic equation
Differential of a quadratic equation (Df)
The differential of quadratic equation
is given by
.
Now the quadratic formula is derived as ![]()
or,
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Note that RHS has two signs(+ and -), so it will give us the two roots which are the two solutions of the quadratic equation
Example 1
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Here
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Discriminant ![]()
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Differential Df ![]()
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Putting in Quadratic formula
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or ![]()
or ![]()
or
Hence
or
are the required solution or roots of the given equation.
Example 2
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Here
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Discernment ![]()
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Differential Df ![]()
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Substitute in Quadratic formula
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or ![]()
or ![]()
or 
i.e
or
are the required solutions
Example 3
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Here
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Discernment ![]()
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Differential ![]()
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Substituting in Quadratic formula
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or ![]()
or ![]()
or ![]()
So here both the solution are same (coincide)
,beacuse discriminant D = 0
Example 4
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here
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Discriminant ![]()
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Here
as
so on real solution or roots are possible for this equation, so we need not proceed further.
Exercise Solution
or ![]()
or
or
or ![]()
or ![]()
or ![]()
or ![]()
or ![]()
or ![]()
or ![]()
Corollary
Special types of quadratic equations which are of Reciprocal type can be solved by observation (Vilokanam) only.
Example 1
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LHS is of reciprocal type so we have to break the RHS into two Reciprocal types
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By comparing on both sides we can observe that
or
are the required solutions.
Example 2
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So, X = 9 or X= 1/9
Example 3
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Here
or ![]()
or ![]()
or ![]()
or
are
The two required solutions (note here that
and
are the reciprocal in LHS)
Exercise Solution
X=5 or X=1/5
X=7 or X=1/7
X=8 or X=-1/8
X = -11/5 or x = -4/5
or ![]()
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